Golden autumn trench coat fashion know

Lead: The summer of inflammation is about to pass. When the cool autumn wind blows, you may miss the warmth of the trench coat. This is not, the autumn fashion trench coat came out, not to go along with Xiao Bian to see.

The scorching summer is about to pass and when the cool autumn wind blows, you may miss the warmth of the trench coat. This is not, the autumn fashion trench coat came out, not to go along with Xiao Bian to see.

金秋风衣时尚早知道(图1)

金秋风衣时尚早知道(图2)

Distorted dress

A unique design of a windbreaker, from the front, you may think it is just an ordinary small jacket, but when you turn, the skirt of the trench coat will be realized. A sense of two things, we must try.

金秋风衣时尚早知道(图3)

Loose outline

Some people think that the windbreaker is too sturdy, and the hard feeling makes people feel that it is not easy enough. Now that the trench coat has a loose outline, how can it be so comfortable?

金秋风衣时尚早知道(图4)

Bright color stack

The coat is only beige and earthy? Then the answer must be wrong. Trench coats are available in a wide range of colors, from prints to dazzling monochromes.

Function pager_path_getFullURL(currentPage, pageSize) { var seoPagerView = "true"; if (seoPagerView == "true") { var searchPagerView = "false"; var noPagePre = "false"; var pageExt = "/"; var param = " ";var fullURL = ""; fullURL += "/article/171977/"; if (searchPagerView == "false") { if (!(currentPage == 1 && pageExt == "/")) { if (noPagePre == "false") { fullURL += "p"; } fullURL += currentPage+pageExt; } }else{ var paramSign = (fullURL.indexOf("?") == -1) ? "?" : "& ";fullURL += paramSign+"page="+currentPage+param; } return fullURL; }else{//Common page path var param = ""; var path = "/article/171977/"; var paramSign = ""; If (param != null && param != "") { paramSign = (path.indexOf("?") == -1) ? "?" : "&" path += paramSign; path += param.replace( "&",""); } if (currentPage != 1) { paramSign = (path.indexOf("?") == -1) ? "?" : "&"; path += paramSign; path += "page="+currentPage; } if (pageSize) { paramSign = (path.indexOf("?") == -1) ? "?" : "&"; path += paramSign; path +="pageSiz e="+pageSize; } return path; } }

Previous 1 2 Next